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what is an equation of the line that passes through the point (-3,1) and is parallel to the line 4x+3y=15?

1 Answer

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equation \: of \: required \: line \implies


4x + 3y + k = 0-----(1)


since \: it \: passes \: through \: ( - 3,1),


- 12 + 3 + k = 0


k = 9


substituting \: in \: k = 9 \: in \: (1),

we get,


4x + 3y + 9 = 0


hence \: the \: equation \: of \: the \: line \implies


\red{ \boxed{ \bold{4x + 3y + 9 = 0}}}

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