Question

A projectile was launched horizontally with a velocity of 468 m/s, 1.86 m above the ground. Calculate how long it would take for the projectile to hit the ground, to the nearest tenth of a second. Record your answer in the boxes below. Be sure to use the correct place value.

Answer 1

0.6 seconds

is ur answer :)

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Answer 2

0.6 seconds

Step-by-step explanation:

The time to fall from height h is ...

t = √(2h/g)

t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.