Question

Help pleaaase!!

A train leaves the station from rest and travels along a straight track. if the train is 500 meters from the station when it reaches a velocity of 50m/s what is the acceleration of the train?

Answer 1

S=D÷T

Step-by-step explanation:

50=0.5÷T

T= 100

Answer 2

`2.5m/s^(2)`

Step-by-step explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

`v^(2) =u^(2) +2as\\50^(2) =0^(2) + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = (2500)/(1000) \\= 2.5m/s^(2)`