Question

Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .

Answer 1

The value is
`L = 0.0073 \ H`

Step-by-step explanation:

From the question we are told that

The number of turns is
`N = 650 \ turns`

The length is
`l = 28 \ cm = 0.28 \ m`

The radius of the cross-section is
`r = 3.5 \ cm = 0.035 \ m`

Generally the cross-sectional area is mathematically represented as

`A = \pi * r^2`

=>
`A = 3.142 * 0.035^2`

=>
`A = 0.00384 \ m^2`

Generally the inductance is mathematically represented as

`L = (N^2 * \mu _o * A )/( l)`

Here
`\mu_o` is the permeability of free space with value
`\mu_o = 4\pi * 10^(-7) N/A^2`

=>
`L = ( 650^2 * 4\pi * 10^(-7) * 0.00384 )/(0.28)`

=>
`L = 0.0073 \ H`