This question is incomplete, the complete question is;
A 1.00 g sample of NH4NO3 is decomposedin a bomb calorimeter. The temperature increases by 6.12°C. What is the molar heat of decomposition for ammonium nitrate?
Molar mass, NH4NO3 80.0 g/mol
Calorimeter Constant 1.23 kJ/°C
Answer:
the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol
Step-by-step explanation:
Given that;
change in temperature ΔT = 6.12 °C
Calorimeter Constant C = 1.23 kJ/°C
Molar mass, NH4NO3 = 80.0 g/mol
we know that;
Heat gained by the calorimeter (Q1) = Heat lost by the decomposition of NH4NO3 (Q2)
Q1 = C × ΔT
Q1 = (1.23 kJ/K) × (6.12 K) = 7.53 kJ
Q value we get becomes negative since we are talking about reaction and not calorimeter
hence
Q1 = - 7.53 kJ
now
1 g NH4NO3 decomposed, - 7.53 kJ of heat is released
so if 80 g which is 1 mol NH4NO3 decompose, the heat will be;
(80 g/mol x -7.53 kJ) / 1 g = - 602.4 kJ/mol
Therefore the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol