66.2k views
0 votes
When an ice cube is placed in a glass of warm water, how are the signs and values q for the ice and the warm water related, assuming no heat is lost from or gained by the glass nor the surrounding air

User JamoBox
by
5.6k points

1 Answer

7 votes

Answer:

q(ice) = -q(warm water)

Step-by-step explanation:

Ice removes energy if ice is put in warm water and ice retains the very same amount of energy. Thus the water temperature heat sign is negative, and the ice heat sign is positive.

User Jhon Didier Sotto
by
5.2k points