Question

How many grams are in 3.01 x 1024 molecules of H2SO4

Answer 1

To determine how many grams are in 3.01 x 10^24 molecules of H2SO4, you convert molecules to moles using Avogadro's number and then multiply by the molar mass of H2SO4, obtaining approximately 490 grams.

Step-by-step explanation:

To calculate how many grams are in 3.01 x 10^24 molecules of H2SO4, you need to perform a series of conversions using the Avogadro's number and the molar mass of sulfuric acid.

First, convert the number of molecules to moles by using Avogadro's number, which is 6.02 x 10^23 molecules per mole:
3.01 x 10^24 molecules H2SO4 × (1 mole H2SO4 / 6.02 x 10^23 molecules) = 5.00 moles H2SO4

Next, calculate the mass by multiplying the moles of H2SO4 by its molar mass. The molar mass of H2SO4 is approximately 98.079 g/mol:

5.00 moles H2SO4 × 98.079 g/mol = 490.395 g
Our final answer, expressed to three significant figures is 490 g of H2SO4.

Answer 2

490. g H₂SO₄

General Formulas and Concepts:

Chemistry - Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

3.01 × 10²⁴ molecules H₂SO₄

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

Step 3: Convert

`3.01 \cdot 10^(24) \ molecules \ H_2SO_4((1 \ mol \ H_2SO_4)/(6.022 \cdot 10^(23) \ molecules \ H_2SO_4) )((98.09 \ g \ H_2SO_4)/(1 \ mol \ H_2SO_4) )` = 490.287 g H₂SO₄

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

490.287 g H₂SO₄ ≈ 490. g H₂SO₄