Question

4 Nitrogen monoxide reacts with oxygen like this:

2NO(gas) + O2(gas) -> 2NO2 (gas)
a. How many moles of oxygen molecules react
with I mole of nitrogen monoxide molecules?
b. What volume of oxygen will react with
50 cm of nitrogen monoxide?
c. Using the volumes in b, what is:
i. the total volume of the two reactants?
ii. the volume of nitrogen dioxide formed?​

Answer 1

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

Further explanation

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

a.

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

`\tt (1)/(2)* 1=0.5`

b.

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

`\tt (1)/(2)* 50~cm^3=25~cm^3`

c.

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³