Question

Find the component form of the vector that translates P(4,5) to p'.

P'(-3,7)

Somebody help!!

Answer 1

The component form of the vector P'P is
`\left \langle -7, 2 \right \rangle`

Explanation:

The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;

The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7

The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2

The component form of the vector P'P =
`\left \langle -7, 2 \right \rangle`