Question

In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=71°, and JH = 2 feet. Find the length of IJ to the nearest tenth of a foot.

Answer 1

IJ is 5.8 ft

Explanation:

Here, we want to calculate the length of IJ

to Find IJ, we need the appropriate trigonometric ratio

The trigonometric ratio to use in this case is the one that connects the opposite and the adjacent

from the question, IJ is the opposite

This is the side facing the given angle

HI is the hypotenuse which is the side facing the right-angle

HJ is the third side which is the adjacent

Mathematically;

That is the Tan

Tan 71 = IJ/2

IJ = 2 Tan 71

IJ = 5.8