Answer:
70.4%
Step-by-step explanation:
Step one:
given data
input energy= 2280J
output energy= 1,606 Joules of useful kinetic and 55joules waste
hence the useful out put= 1606J
Required
The efficiency of the motor
Step two:
what is the efficiency of a motor?
efficiency is the ratio of mechanical power delivered by the motor (output) to the electrical power supplied to the motor (input)
Efficiency= 1606/2280*100
Efficiency=0.704*100
Efficiency=70.4%