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The mass of Ba(CIO), formed when 0.50 mole of Ba(OH), is treated with 0.80 mol of HCIO, according to the reaction below is
Ba(OH), + 2HCIO, ----> Ba(CIO3)2 + 2H,0
Ba: 137.3 g/mol
O: 16 g/mol
H: 1 g/mol
Cl: 35.45 g/mol
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16
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304 2 g
243.4 g
121.79
380.7 g
None of the above
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Answer 1

The mass of Ba(CIO₃)₂ : 121.72 g

Further explanation

Reaction

Ba(OH)₂ + 2HCIO₃ ----> Ba(CIO₃)₂ + 2H₂O

Limiting reactant :

Ba(OH)₂ : 2HCIO₃ =

`\tt (0.5)/(1)/ (0.8)/(2)=0.5/ 0.4\rightarrow HClO_3~limiting(smaller~ratio)`

mol Ba(CIO₃)₂ based on limiting reactant(HCIO₃) :

`\tt (1)/(2)* 0.8=0.4`

MW Ba(CIO₃)₂ =Ba+2.Cl+6.O=137.3 + 2 x 35.5 + 6 x 16 = 304.3

mass of Ba(CIO₃)₂ :

`\tt mass=mol* MW\\\\mass=0.4* 304.3=121.72~g`