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Determine the sum of the exterior angles in a convex 50-gon. (G.10)(1 point)

Determine the sum of the exterior angles in a convex 50-gon. (G.10)(1 point)-example-1
User Mbcrute
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Answer:

The sum of the exterior angles in a convex 50-gon polygon is 360° ⇒ A

Explanation:

  1. The formula of the sum of the interior angles of any polygon is ∑ = (n - 2) × 180°, where, n is the number of the sides or the angles of the polygon
  2. The sum of the measures of the interior angle and the exterior angle at a vertex of the polygon is 180°
  3. The sum of the exterior angles of any polygon (n-gon) is 360°

In the question

∵ The polygon has 50 sides

→ By using the 3rd rule above

∵ The sum of the exterior angles of any polygon (n-gon) is 360°

The sum of the exterior angles in a convex 50-gon polygon is 360°

User Dsplatonov
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