Question

PLEASE HELP ME

A motor takes 2,280 Joules of electrical energy and turns it into 1,606 Joules
of useful kinetic energy and 550 Joules of wasted thermal energy and sound.
Calculate the efficiency of the motor in percent.

Answer 1

Given that,

Electrical energy of the motor = 2280 J

Kinetic energy = 1606 J

Wasted energy in thermal and sound energy = 550 J

To find,

The efficiency of the motor in percent.

Solution,

Efficiency is defined as the ratio of useful output energy to the total energy.

Total energy = 2280 J

Useful energy = 1606 J

`\eta=(1606)/(2280)* 100\\\\=70.43\%`

So, the efficiency of the motor is 70.43%.