Question

What pressure would 2.5 moles of N2 gas exerton the walls of a 10.0 L container at a temperature of 25 C (298 K)

Answer 1

6.1 atm

General Formulas and Concepts:

Chemistry - Gas Laws

Combined Gas Law: PV = nRT

• P is pressure in atm
• V is volume in Liters
• n is number of moles
• R is the gas constant: 0.0821 (L · atm)/(mol · K)
• T is temperature in Kelvins

Temperature Conversion: K = °C + 273.15

Step-by-step explanation:

Step 1: Define

n = 2.5 mol N₂

V = 10.0 L

T = 25 °C = 298.15 K

Step 2: Find Pressure P

1. Substitute: P(10 L) = (2.5 mol)(0.0821 (L · atm)/(mol · K)(298.15 K)
2. Multiply: P(10 L) = 61.1953 L · atm
3. Isolate P: P = 6.11953 atm

Step 3: Check

We are given 2 sig figs as our lowest. Follow sig figs and round.

6.11953 atm ≈ 6.1 atm