Question

A student jumps off of a cliff into a river 25.9 m below. If the student landed 20.7 m horizontally away from where they jumped how much time was the student airborne?

Answer 1

The student was airborne for approximately 2.3 seconds.

Step-by-step explanation:

First, let's find the time the student was airborne using the horizontal distance:

Use the formula for horizontal distance: d = vt, where d is the distance, v is the horizontal velocity, and t is the time.

Substitute the given values: 20.7 m = v * t.

Next, use the formula for vertical distance: d = 0.5 * g * t^2, where d is the vertical distance, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.

Substitute the given values: 25.9 m = 0.5 * 9.8 m/s^2 * t^2.

Solve the equation for t: t = sqrt((2 * 25.9 m) / (9.8 m/s^2)).

Calculate the time: t = sqrt(5.28 s^2).

Therefore, the student was airborne for approximately 2.3 seconds.