Question

How many moles of gas does it take to occupy 150 L at a pressure of 4.2 atm and a temperature of 389 K?

Answer 1

Moles of gas=19.75

Further explanation

The gas equation can be written

`\large {\boxed {\bold {PV = nRT}}}`

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

V=150 L

P=4.2 atm

T=389 K

`\tt n=(PV)/(RT)\\\\n=(4.2* 150)/(0.082* 389)\\\\n=19.75`