Question

A 60.0 g sample of chromium at 82.0°C (specific heat for chromium is 0.11 J/g°C) was placed in 80.0 g of water. Assume there is no loss of heat to the environment. What is the temperature of the water and the chromium? The water's initial temperature was 24.0°C.

Answer 1

The temperature of the water and the chromium : 25.122 ° C

Further explanation

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released

Q in(gained) = Q out (lost)

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Q Chromium= Q water

`\tt 60* 0.11* (82-t)=80* 4.18* (t-24)\\\\541.2-6.6t=334.4t-8025.6\\\\341t=8566.8\\\\t=25.122^oC`