Question

3. Decomposition of a sample of KCIO3(s) produced 25.2 mL of 020, at a temperature of

27°C and a pressure of 89.6 kPa. What is the volume, in ml, of this oxygen gas at 45°C
and a pressure of 89.6 kPa ?

Answer 1

The volume of Oxygen gas=26.712 ml

Further explanation

The pressure constant = 89.6 kPa, so we use Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

`\tt (V_1)/(T_1)=(V_2)/(T_2)`

V₁=25.2 ml

T₁=27+273=300 K

T₂=45+273=318 K

`\tt V_2=(V_1* T_2)/(T_1)\\\\V_2=(25.2* 318)/(300)\\\\V_2=26.712~ml`