Question

How many particles are in 47.7 g of Magnesium? (Round the average

atomic mass to two numbers after the decimal)

Answer 1

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

Chemistry - Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Step 3: Convert

`47.7 \ g \ Mg((1 \ mol \ Mg)/(24.31 \ g \ Mg) )((6.022 \cdot 10^(23) \ particles \ Mg)/(1 \ mol \ Mg) )` = 1.18161 × 10²⁴ particles Mg

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg