Question

7. A monkey freefalls for 17.5 seconds. (a) What was the velocity after this time? (b) How far did it fall?

Answer 1

a ) Vf = 171.7 [m/s]

b) y = 1502.6[m]

Step-by-step explanation:

a) To solve this problem we must use the following equation of kinematics.

`v_(f)=v_(o)+g*t`

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (freefall, without initial velocity)

g = gravity acceleration = 9.81 [m/s²]

t = time = 17.5 [s]

Now replacing:

`v_(f) = 0 + 9.81*17.5\\v_(f) = 171.7[m/s]`

Note: The gravity acceleration is positive, since the monkey is moving in the direction of the gravity acceleration.

b)

Now using another equation of kinematics we can calculate the distance traveled.

`v_(f)^(2)=v_(o)^(2)+2*g*y`

where:

y = distance traveled [m]

`171.7^(2)=0 +2*9.81*y\\y=29480.9/(2*9.81)\\y=1502.6[m]`