Question

What is the pressure of 1.50 moles of a gas in a 30.0L tank at a temperature of
285K?

Answer 1

The pressure of the gas : 1.1685 atm

Further explanation

In general, the gas equation can be written

`\large {\boxed {\bold {PV = nRT}}}`

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

n=moles=1.5

V=volumes = 30 L

T=temperature=285 K

The pressure :

`\tt P=(nRT)/(V)\\\\n=(1.5* 0.082* 285)/(30)\\\\P=1.1685~atm`