Question

What would this question look like after we change the mixed number to improper & use KCF to rewrite the question?

h) 3 1/2 divided by 1/3 =
A) 7/2 x 1/3
B) 7/2 x 3/1
C) 6/2 x 1/3
D) 7x3
Hurry !!

Answer 1

The question
`3(1)/(2)/(1)/(3)` after change the mixed number to improper & using KCF will become :
`\mathbf{=(7)/(2)* (3)/(1)}`

Option B is correct option.

Explanation:

We need to change the mixed number to improper & use KCF to rewrite the question.

The expression is:
`3(1)/(2)/(1)/(3)`

First converting mixed fraction into improper fraction

Multiply whole number with the denominator i,e (3*2=6) now add the numerator i.e (6+1) = 7/2

Solving:

`3(1)/(2)/(1)/(3)\\=(7)/(2)/(1)/(3)`

Using KCF

KCF stands fro Keep it, Change it, Flip it.

It is used when division sign is converted to multiplication the term (1/3) is reversed to (3/1)

So, our expression will be

`=(7)/(2)* (3)/(1)`

So, The question
`3(1)/(2)/(1)/(3)` after change the mixed number to improper & using KCF will become :
`\mathbf{=(7)/(2)* (3)/(1)}`

Option B is correct option.