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Write an equation for the line that passes through (2,-5) and is parallel to the line 2y=3x+10

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Answer:


y = (3)/(2) x-8

Explanation:

Firstly, let's get y by itself in the equation.


y = (3)/(2)x + 5

Parallel lines have the same slope, but not the same y intercept. So we have an equation like this:


y = (3)/(2)x + b

To find b (aka the y-intercept), we need to plug in the ordered pair into the equation like this:


-5 = (3)/(2)(2) + b

Now solve:


-5 = (6)/(2) + b\\-5 = 3 + b\\-8 = b

We have found the y-intercept, now we can write the full equation:


y = (3)/(2) x-8

I hope this helps!!

- Kay :)

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