Question

determine the force of gravitational attraction between a 78 kg boy sitting 2 meters away from a 65 kg girl. circle your answer and include units

Answer 1

The force of gravitational attraction is 8.454 x 10⁻⁸ N.

Step-by-step explanation:

Given;

mass of the boy, m₁ = 78 kg

mass of the girl, m₂ = 65 kg

distance between the boy and the girl, r = 2 meters

The force of gravitational attraction is given as;

`F = (Gm_1m_2)/(r^2)`

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

r is the distance between two masses, m₁ and m₂

`F = (Gm_1m_2)/(r^2) \\\\F = ((6.67 * 10^(-11))(78 * 65))/(2^2)\\\\F = 8.454 * 10^(-8) \ N`

Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.