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An airplane is flying at 32,000 feet when it starts it’s decent. It is
descending at a rate of 2000 feet per minute. Let x represent the minutes
of the flights descent and y represent the plane’s altitude.

a. Fill in the table.
b. Write an equation in slope-intercept form for the plane’s altitude.
c. Graph the equation from part (b).

2 Answers

3 votes

Answer:

10,000

Step-by-step explanation:

f = feet above ground

r = rate of descent

m = minutes

f = 30000 - r · m

f = 30000 - 20000m

After five minutes:

f = 30000 - 2000(5)

f = 30000 - 10000

f = 20000

After five minutes the plane is at 10,000. feet.

User Royeet
by
6.4k points
3 votes

Final answer:

The plane's altitude decreases linearly as it descends. The required equation in slope-intercept form is y = -2000x + 32000, which shows the relationship between time x and altitude y during descent. To graph it, start at 32,000 feet and plot the linear decrease of 2,000 feet per minute.

Step-by-step explanation:

To solve this problem, we first need to determine how the plane's altitude changes as time passes during its descent. Since the airplane starts at 32,000 feet and descends at a rate of 2,000 feet per minute, for every minute x that passes, the altitude y decreases by 2,000 feet. Therefore, after x minutes, the plane's altitude y will be 32,000 feet minus 2,000 times x feet.

The equation in slope-intercept form is y = -2000x + 32000. Here, -2000 represents the rate of descent (slope), and 32000 represents the starting altitude (y-intercept).

To graph the equation, plot the y-intercept (0, 32000) on the y-axis. For each minute that passes (increase in x), descend 2,000 feet on the y-axis. Connect the points to show the linear decrease in altitude over time.

User Murtza Gondal
by
6.6k points