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Reduced form of 2ab^2-a^2 b^2/5

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Answer:


2ab^2-(a^2b^2)/(5)=(10ab^2-a^2b^2)/(5)

Explanation:

Given the expression


2ab^2-(a^2b^2)/(5)


\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=(2ab^25)/(5)


2ab^2-(a^2b^2)/(5)=(2ab^2\cdot \:5)/(5)-(a^2b^2)/(5)


\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad (a)/(c)\pm (b)/(c)=(a\pm \:b)/(c)


=(2ab^2\cdot \:5-a^2b^2)/(5)


=(10ab^2-a^2b^2)/(5)

Thus,


2ab^2-(a^2b^2)/(5)=(10ab^2-a^2b^2)/(5)

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