Answer:
a. 754cm³ (3 s.f.)
b. 415cm² (3 s.f.)
Explanation:
Formulas (for easier reference):
Volume of cone:
r²
Volume of hemisphere:
![(2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/54kd5otoayi7fslqp2ejx77tdkhh8ubevy.png)
r³
Surface area of cone without base:
rl
Surface area of hemisphere without base: 2
r²
We can just apply the formulas for the question:
Volume of toy = (
× 6² ×
) + (
×
6³)
= 96
+ 144
= 240
![\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/2j2worn9ytoxzzhoj9a714ilg18jf2lvx4.png)
= 754cm³ (3 s.f.)
Surface area of toy = (
× 6 × 10) + (2 ×
× 6²)
= 60
+ 72
![\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/2j2worn9ytoxzzhoj9a714ilg18jf2lvx4.png)
= 132
![\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/2j2worn9ytoxzzhoj9a714ilg18jf2lvx4.png)
= 415cm² (3 s.f.)