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Please help.............

Please help.............-example-1
User Brianfit
by
5.3k points

1 Answer

3 votes

Answer:

a. 754cm³ (3 s.f.)

b. 415cm² (3 s.f.)

Explanation:

Formulas (for easier reference):

Volume of cone:
\pi
(h)/(3)

Volume of hemisphere:
(2)/(3)
\pi

Surface area of cone without base:
\pirl

Surface area of hemisphere without base: 2
\pi

We can just apply the formulas for the question:

Volume of toy = (
\pi × 6² ×
(8)/(3)) + (
(2)/(3) ×
\pi 6³)

= 96
\pi + 144
\pi

= 240
\pi

= 754cm³ (3 s.f.)

Surface area of toy = (
\pi × 6 × 10) + (2 ×
\pi × 6²)

= 60
\pi + 72
\pi

= 132
\pi

= 415cm² (3 s.f.)

User Elimelech
by
5.3k points
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