Given that,
The coordinates of A = (-10,-8)
The coordinates of B = (80,37)
To find,
The coordinates of a point that partitions segment AB in a ratio of 4:5.
Solution,
Let the coordinate of required point is (x,y). We can use section formula to find it as follows :
The section formula is :
![(x,y)=((m_2x_1+m_1x_2)/(m_1+m_2),(m_2y_1+m_1y_2)/(m_1+m_2),)](https://img.qammunity.org/2021/formulas/mathematics/college/x11vf0gqr7zkdt11y607rx16t67gmrk4ld.png)
We have,
m₁ =4, m₂ = 5, x₁ = -10, x₂ = 80, y₁ = -8, y₂ = 37
Using all the values,
![(x,y)=((5(-10)+4(-10))/(4+5),(5(-8)+4(37))/(4+5))\\\\=(-10,12)](https://img.qammunity.org/2021/formulas/mathematics/college/2n5a2lyjn631uwpaswyyjyxv6zwc3d9ut3.png)
So, the required point in which AB is divided is (-10,12)