Question

What is the molarity of a solution prepared by dissolving 1.25g of HCl gas

into enough water to make 30cm3 of solution

Answer 1

The molarity of a solution : 1.13 M

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

`\large \boxed {\bold {M ~ = ~ \frac {n} {V}}}`

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

mass HCl = 1.25 g

mol HCl(MW=36.5 g/mol) :

`\tt mol=(mass)/(MW)\\\\mol=(1.25)/(36.5)\\\\mol=0.034`

Volume of solution = 30 cm³ = 0.03 L

The molarity :

`\tt M=(0.034)/(0.03)\\\\M=1.13`