Question

A results force of 25newtons acts on a mass of 0.50kilogram starting from rest .find acceleretion in m/s2 , the final velocity after 20seconds, the distance moved in m

Answer 1

Answer: See below

Step-by-step explanation:

a) Using Newton's 2nd Law, rearranging and solving for acceleration

`a &= (F)/(m)\\ &= \frac{25\ \text{N}}{0.5\ \text{kg}}\\ &= \boxed{50\ \text{m/s}^2}`

b) Using the acceleration 50 m/s^2 and the initial velocity v = 0 (since the object starts from rest), the final velocity at t = 20, v can be determined using a suitable equation as follows:

`v &= u+ at\\ &= 0+ 50\ \text{m/s}^2(20\ \text{s})\\ &= \boxed{100\ \text{m/s}}`

c) To determine the distance s traveled in the 20 seconds, we'll use a suitable equation:

`s &= ut+(1)/(2)at^2\\ &= 0+(1)/(2)(50 \text{m/s}^2)(20\ \text{s})^2\\ &= \boxed{10\ 000\ \text{m}}`