Question

Find the equation of the line that passes through the following points. Write the equation in slope-intercept form.

(-4.-8) and (-8, -9)

Answer 1

The equation in the slope-intercept form will be:

y = 1/4x - 7

Explanation:

Given the points

• (-4.-8)

• (-8, -9)

`\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)`

`\left(x_1,\:y_1\right)=\left(-4,\:-8\right),\:\left(x_2,\:y_2\right)=\left(-8,\:-9\right)`

`m=(-9-\left(-8\right))/(-8-\left(-4\right))`

`m=(1)/(4)`

We know that the slope-intercept of line equation is

`y=mx+b`

where m is the slope and b is the y-intercept

substituting m = 1/4 and the point (-4, -8) to find the y-intercept 'b'

y = mx+b

-8 = 1/4(-4)+b

-8 = -1 + b

b = -8+1

b = -7

so the y-intercept = b = -7

substituting m = 1/4 and b = -7 in the slope-intercept form of line equation

y = mx+b

y = 1/4x + (-7)

y = 1/4x - 7

Thus, the the equation in slope-intercept form will be:

y = 1/4x - 7