130k views
3 votes
A 1520 kg car is rolling

down a frictionless
14.4° slope. What is
its acceleration?

User Jumpdart
by
5.9k points

2 Answers

3 votes

Answer:

2.44

Step-by-step explanation:

If your on Acellus the correct answer is 2.44

User Indrek
by
6.1k points
6 votes

Answer:

a = 2.44 m/s²

Step-by-step explanation:

The Net force acting on the car downwards the plane will be equal to the component of the weight that is parallel to the plane.

Thus;

mg(sin θ) = ma

Thus;. g(sin θ) = a

g is acceleration due to gravity = 9.81 m/s²

θ = 14.4°

Thus;

9.81 × sin 14.4 = a

a = 2.44 m/s²

User Brian Muenzenmeyer
by
5.5k points