Question

Write the standard form of the equation of the circle with center (−7,1) that passes through the point (−7,9).

Answer 1

(x + 7)² + (y - 1)² = 64

Explanation:

Use the equation of a circle, (x - h)² + (y - k)² = r²

Plug in the point and center, then solve for r:

(x - h)² + (y - k)² = r²

(-7 + 7)² + (9 - 1)² = r²

0 + 64 = r²

64 = r²

8 = r

Then, plug in the center and r² into the equation:

(x + 7)² + (y - 1)² = 64

So, (x + 7)² + (y - 1)² = 64 is the standard form of the circle's equation