Question

Does the MVT apply? Explain why or why not.
y=x^2/4x + 4 ;
[-6, -2]

Answer 1

Hello!

`\large\boxed{\text{Yes, it does.}}`

In order to use the MVT, the function must be continuous over the given interval.

`y = (x^(2) )/(4x)+4`

Simplifies to:

`y = (x)/(4) + 4`

This is a linear equation that is continuous on the interval (-∞, ∞), which means that it would also be continuous on the interval [-6, -2]. The MVT would apply to this function.