505,246 views
8 votes
8 votes
(x-8)^2 i need step by step please like eveyone gets x2 -16x +64 i dont get
how

User Elcudro
by
3.1k points

2 Answers

27 votes
27 votes

Answer:

x²-16x+64

  • use formula =a²-2ab+b²
  • x²-2.x.8+8² (for knowledge 2 × 8 = 16)
  • x²-16x+64
User Nathan Horrigan
by
3.1k points
19 votes
19 votes

Answer:

(x -8)² = x² -16x +64

Explanation:

A lot of math is about pattern recognition. For many of the patterns you are asked to recognize, it is helpful to be very familiar with basic math facts: addition facts, multiplication facts, and the squares and cubes of small integers.

All of algebra is based on a few properties of arithmetic and equality. One that is important here is the distributive property.

__

expanding a product of binomials

One of the patterns that is used with quadratics is the square of a binomial.

(a - b)² = a² -2ab +b²

This is the result of applying the distributive property several times.

First of all, the exponent indicates repeated multiplication:

(a -b)² = (a -b)×(a -b)

The distributive property tells you each term outside parentheses multiplies each term inside:

= a×(a -b) -b×(a -b)

= a·a -a·b -b·a +b·b . . . . . and again

Now, we collect terms, recognizing that ab=ba.

= a² -2(a·b) +b² . . . . . . . using exponents for repeated multiplication

So, the pattern for the square of a binomial is ...

(a -b)² = a² -2ab +b²

__

using the pattern

For your specific case, ...

  • a = x
  • b = 8

(x -8)² = x² -2(x)(8) +8² . . . . . . using the above pattern

(x -8)² = x² -16x +64

_____

Additional comment

If you want to do this without using the pattern, just make use of the distributive property:


(x-8)^2=(x-8)(x-8)\\\\=x(x -8) -8(x-8)\\\\=x^2-8x-(8x-64)\\\\=x^2-8x-8x+64\\\\\boxed{(x-8)^2=x^2-16x+64}}

__

While the distributive property is the fundamental property involved, some find it helpful to remember a mnemonic that gets you to the same result for the product of binomials: FOIL. The letters refer to First, Outer, Inner, Last, and they remind you of the terms that make up the expansion of the product:

  • (x -8)(x -8) -- First: x·x = x²
  • (x -8)(x -8) -- Outer: x·(-8) = -8x
  • (x -8)(x -8) -- Inner: (-8)·x = -8x
  • (x -8)(x -8) -- Last: (-8)(-8) = 64

Then the product is ...

(x -8)² = x² -8x -8x +64 = x² -16x +64

__

Of course, the distributive property is involved in what we call "collecting terms."

-8x -8x = (-8-8)x = -16x

The variable is factored out using the distributive property, then the coefficients are added to simplify the expression in parentheses.

User Friveraa
by
3.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.