Question

How many moles of LiCl will I have if I start off with .425 moles of CaC12?

Answer 1

The equation is

`\\ \tt{:}\dashrightarrow LiOH+CalCl_2\longrightarrow LiCl+Ca(OH)_2`

• This is balanced

1mol of LiCl needs 1 mol CaCl_2

Then

0.425mol of CaCl_2 will produce 0.425mol LiCl

Answer 2

• LiOH+CaCl_2—»LiCl+Ca(OH)_2

Balanced

Moles of CaCl_2=0.425mol

1 mol CaCl_2 producees 1 mol LiCl

Moles of LiCl

• 0.425(1)
• 0.425moles