Question

Can someone plsss help me in this.

Answer 1

`x \ = \ √(31) \ \text{m}`

Explanation:

Since both triangles are right triangles, we then can leverage the Pythagorean Theorem.

Let the length of hypothenuse of the smaller triangle be
`\gamma` , hence

`\gamma^(2) \ = a^(2) \ - \ b^(2) \\ \\ \gamma^(2) \ = \ \left(6\right)^(2) \ - \ \left(2\right)^(2) \\ \\ \gamma^(2) \ = \ 36 \ - \ 4 \\ \\ \gamma^(2) \ = \ 32`

Subsequently,

`\gamma^(2) \ = \ c^(2) \ + \ x^(2) \\ \\ \gamma^(2) \ - \ c^(2) = \ x^(2) \\ \\ x^(2) \ = \ 32 \ - \ \left(1\right)^(2) \\ \\ x^(2) \ = \ 32 \ - \ 1 \\ \\ x^(2) \ = \ 31 \\ \\ x \ = \ √(31)`

Answer 2

first you need to find how long the side of the ab triangle is

so to find it you use the reciprocal Pythagorean theorem c2= a2-b2

so a2 -b2 = 6*6-2*2 = 30

so now we now that the side of the ab traingle is the square root of 30

then to find x you use the reciprocal Pythagorean theorem again and it goes x2= 30-c2

so x2= 30 -1*1 = 29

x = the square root of 29

Explanation:

that should do it