Answer:
The distance from the plane to the building is ___2553.2___meters.
Explanation:
Given that An airplane is at an altitude of 1200 m.
The angle of depression to a building at the airport on the ground measures 28°.
We need to find the distance from the plane to the building.
Please check the attached diagram.
Let 'x' be the required distance in meters.
It forms a right-angled triangle as shown in the attached diagram.
The angle = Ф = 28°
The opposite to angle = 1200 meters
All we need to find the hypotenuse to determine the distance from the plane to the building.
Using the trigonometric ratio
sin θ = Perpendicular ÷ Hypotenuse
sin (28°) = 1200 ÷ x
x = 1200/sin (28°)
= 1200 / 0.47 ∵ sin (28°) = 0.47
= 2553.2 m
Thus, the distance from the plane to the building is ___2553.2___meters.