Question

If you dilute 19.0 mL of the stock solution to a final volume of 0.310 L , what will be the concentration of the diluted solution?

Answer 1

`M_2=0.613M_1`

Step-by-step explanation:

`M_1` = Concentration of stock solution

`M_2` = Concentration of solution

`V_1` = Volume of stock solution = 19 mL

`V_2` = Volume of solution = 0.31 L= 310 mL

We have the relation

`M_1V_1=M_2V_2\\\Rightarrow M_2=(M_1V_1)/(V_2)\\\Rightarrow M_2=(M_119)/(310)\\\Rightarrow M_2=M_1*(19)/(310)\\\Rightarrow M_2=0.613M_1`

`\boldsymbol{\therefore M_2=0.613M_1}`

The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.