Question

The perimeter of a rectangle is 56 cm. When its length is reduced by 2 cm and its

width is increased by 4 cm, a square is formed. What is the area of the rectangle ?​

Answer 1

187 cm squared.

Based on rectangle:

2L + 2W = 56

Draw the square and name your sides the following:
(W+4) , (L-2), (W+4), (L-2)

Because it’s a square, all sides are equal and we can remove and solve for one of the variables but keep in mind the parameter changed..

The new parameter is 56 minus 4cm + 8cm...keep in mind I used 4cm and 8cm because we have a 2 Lengths and 2 Widths.

Solving 60= 4 (w+4)
W= 11

So the side of our square is 11+4=15

L-2 = 15
L=17

So the area of the Rectangle is 11*17=187 cm squared.

Please let me know if it’s correct !