Question

A sample of gas occupies a volume of 571.5 mL at 0.944 atm and 10 oC. Determine the pressure of this sample at 1.183 L and 32 oC.

Answer 1

0.491 atm

Step-by-step explanation:

Initial volume V1 = 571.5 mL = 0.5715 L

Initial Pressure P1 = 0.944 atm

Initial Temperature T1 = 10 oC + 273 = 283 K (Converting to kelvin units)

Final Temperature T2 = 32 oC + 273 = 305K (Converting to kelvin units)

Final volume V2 = 1.183 L

Final Pressure P2 = ?

These parameters related by the combined gas law;

P1V1 / T1 = P2V2 / T2

Mke P2 subject of formular;

P2 = P1 V1 T2 / V2 T1

P2 = 0.944 * 0.5715 * 305 / 1.183 * 283

P2 = 0.491 atm