Question

What are the respective concentrations (M) of Mg2+and Cl-afforded by dissolving 0.325 mol MgCl2 in water and diluting to 250 mL?A) 0.0013 and 0.0013B) 0.0013 and 0.0026C) 1.30 and.1.30D) 1.30 and 2.60E) 2.60 and 2.60

Answer 1

Answer: D) 1.30 and 2.60

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

molarity of
`MgCl_2` =
`(0.325* 1000)/(250ml)=1.30 M`

`MgCl_2\rightarrow Mg^(2+)+Cl^(-)`

As 1 mole of
`MgCl_2` dissociates to give one mole of
`Mg^(2+)` and two moles of
`Cl^-` ions .

Molarity of
`Mg^(2+)` = 1.30 M

Molarity of
`Cl^(-)` =
`1.3 M* 2=2.60M`