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You have a Direct Mapped cache with following parameters Cache Data Size (C) 128 Block Size (b) 4 After partitioning the address, which is 32 bits big, into Tag, Set, and Offset, how many bits will be
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You have a Direct Mapped cache with following parameters

Cache Data Size (C) 128
Block Size (b) 4
After partitioning the address, which is 32 bits big, into Tag, Set, and Offset, how many bits will be in each field?

User Mocktheduck
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Yes... so it would be 134 seeing as, 128 and 4 both common denominators.. and the offset would be to the 40%
User Bachmann
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