Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
![(I_1)/(I_2)=(r_2^2)/(r_1^2)\\\\r_2^2=(I_1r_1^2)/(I_2)\\\\r_2^2=(60* (3)^2)/(15)\\\\r_2=6\ m](https://img.qammunity.org/2021/formulas/physics/college/clbjeuus12gy4zbyt6ag5d5xffm2i0layp.png)
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.