Answer:
(- 5, - 3 )
Explanation:
Given the 2 equations
- 3x + 10y = - 15 → (1)
5x - 7y = - 4 → (2)
Multiplying (1) by 5 and (2) by 3 and adding the result, eliminates the x- term.
- 15x + 50y = - 75 → (3)
15x - 21y = - 12 → (4)
Add (3) and (4) term by term to eliminate x, that is
29y = - 87 ( divide both sides by 29 )
y = - 3
Substitute y = - 3 into either of the 2 equations and solve for x
Substituting into (1)
- 3x + 10(- 3) = - 15
- 3x - 30 = - 15 ( add 30 to both sides )
- 3x = 15 ( divide both sides by - 3 )
x = - 5
solution is (- 5, - 3 )