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1/sin10°-√3/cos10°=4​

User Kgdesouz
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1 Answer

6 votes

Answer:


(1)/(\sin \left(10^(\circ \:\:)\right))\:\:(1)/(\sin \:\left(10^(\circ \:\:)\right))=4

Explanation:

Given the expression


(1)/(\sin \left(10^(\circ \:)\right))-(√(3))/(\cos \left(10^(\circ \:)\right))=4

Taking the left-hand side and solving it


(1)/(\sin \left(10^(\circ \:)\right))-(√(3))/(\cos \left(10^(\circ \:)\right))

as


(1)/(\sin \:\left(10^(\circ \:\:)\right))=5.76

and


(√(3))/(\cos \left(10^(\circ \:\:)\right))=1.76

so the expression becomes


(1)/(\sin \left(10^(\circ \:\:)\right))\:\:(1)/(\sin \:\left(10^(\circ \:\:)\right))=5.76-1.76


=4

Thus, we conclude that


(1)/(\sin \left(10^(\circ \:\:)\right))\:\:(1)/(\sin \:\left(10^(\circ \:\:)\right))=4

User DKA
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