Question

A solution is made

by dissolving
29 g of sodium lithium chloride
in water to a final volume of
202 mL solution.
What is the weightweight % or percent by mass of the somute
percent by mass of the solute?

Answer 1

Answer: 14.3

Step-by-step explanation:

Answer 2

99.3%

Step-by-step explanation:

The percent by mass of the solute can be expressed as:

• % mass =
  `(MassSolute)/(MassSolute+MassSolvent)` * 100%

And for this problem:

• Mass of Solute = Mass of sodium lithium chloride = 29 g

• Mass of Solvent = Mass of Water

So to calculate the percent by mass first we need to calculate the mass of water, to do so we use its density (1 g/L):

• 202 mL is equal to (202/1000) 0.202 L.

Density water = mass water / volume

• 1 g/L = mass water / 0.202 L

• Mass water = 0.202 g

Now we have all the data required to calculate the % mass:

• % mass =
  `(29g)/(29g+0.202g)` * 100 % = 99.3%