Question

A running person has a what you need. Mass of 60kg and a speed of 3.16m/s what is her kinetic energy?

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Answer 1

We know that, Kinetic energy(kE)= 1/2×m×v^2

By applying formula,we get

Or,KE=1/2×60×3.16^2

Or,kE=299.57j

So,her kinetic energy is 2999.5j

Answer 2

`\boxed {\boxed {\sf 299.568 \ Joules }}`

Step-by-step explanation:

Kinetic energy can be found using the following formula:

`E_k=(1)/(2)mv^2`

where m is the mass and v is the velocity.

The mass of the person is 60 kilograms and the velocity is 3.16 meters per second

`m= 60 \ kg \\v= 3.16 \ m/s`

Substitute the values into the formula.

`E_k=(1)/(2) (60 \ kg) *(3.16 \ m/s)^2`

First, evaluate the exponent.

• (3.16 m/s)²= (3.16 m/s) * (3.16 m/s) = 9.9856 m²/s²

`E_k=(1)/(2)(60 \ kg ) (9.9856 \ m^2/s^2)`

Multiply 60 kg by 9.9856 m²/s²

`E_k=(1)/(2) (599.136 \ kg*m^2/s^2)`

Multiply 599.136 kg*m²/s² by 1/2, or divide by 2.

`E_k=299.568 \ kg*m^2/s^2`

• 1 kg*m²/s² is equal to 1 Joule

• Therefore, our answer of 299.568 kg*m²/s² is equal to 299.568 Joules.

`E_k= 299.568 \ J`

The running person has a kinetic energy of 299.568 Joules.