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A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical components of its velocity after 5.5s

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Answer:


v_x=34 m/s


v_y=53.9\ m/s

Step-by-step explanation:

Horizontal Launch

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:


v_y=g.t

The horizontal component of the velocity is always the same:


v_x=34 m/s

The vertical component at t=5.5 s is:


v_y=9.8*5.5=53.9


v_y=53.9\ m/s

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